Given an integer array arr and a mapping function fn, return a new array with a transformation applied to each element.
The returned array should be created such that returnedArray[i] = fn(arr[i], i).
Please solve it without the built-in Array.map method.
Example 1:
Input: arr = [1,2,3], fn = function plusone(n) { return n + 1; }
Output: [2,3,4]
Explanation:
const newArray = map(arr, plusone); // [2,3,4]
The function increases each value in the array by one.
Example 2:
Input: arr = [1,2,3], fn = function plusI(n, i) { return n + i; }
Output: [1,3,5]
Explanation: The function increases each value by the index it resides in.
Example 3:
Input: arr = [10,20,30], fn = function constant() { return 42; }
Output: [42,42,42]
Explanation: The function always returns 42.
Constraints:
0 <= arr.length <= 1000-109 <= arr[i] <= 109fn returns an integer.When you get asked this question in a real-life environment, it will often be ambiguous (especially at FAANG). Make sure to ask these questions in that case:
The goal is to create a new collection of numbers where each number is transformed based on a specific rule. The brute force approach involves going through each number in the original collection one by one and applying the transformation to it.
Here's how the algorithm would work step-by-step:
def apply_transform(original_array, transform_function):
transformed_array = []
# Iterate through each element of the original array
for array_index in range(len(original_array)):
# Get the current element from the array
current_element = original_array[array_index]
# Apply the transformation function to the element
transformed_element = transform_function(current_element)
# Append the transformed element to the new array
transformed_array.append(transformed_element)
# Return the new array with transformed elements
return transformed_arrayThe best way to solve this is to go through each element in the input one by one. For each element, we apply a given rule and save the result. At the end, we simply return the result.
Here's how the algorithm would work step-by-step:
def apply_transform_over_each_element_in_array(input_array, transform_function):
transformed_array = []
# Iterate through each element of the input array
for element in input_array:
# Apply the transformation function to the current element
transformed_element = transform_function(element)
# Add the transformed element to the result array
transformed_array.append(transformed_element)
# Return the array containing the transformed elements
return transformed_array| Case | How to Handle |
|---|---|
| Null or undefined input array nums | Return an empty array or throw an error based on the problem's specific requirements. |
| Empty input array nums | Return an empty array as there are no elements to transform. |
| Null or undefined function fn | Throw an error since the transformation cannot be applied without a valid function. |
| fn throws an error during execution | Catch the exception thrown by fn and handle it appropriately, either by logging the error or re-throwing it. |
| Large input array nums (close to memory limits) | Ensure that the new array creation doesn't cause memory overflow; consider in-place transformation if feasible. |
| Function fn returns non-numeric values | Type-check the returned value of fn and handle it based on the expected output type of the transformed array. |
| Function fn has side effects | Document this behavior or discourage it as side effects can make debugging and reasoning about the code harder. |
| nums contains very large numbers | Consider potential for integer overflow in the transformed array if fn involves arithmetic operations. |