You own a Goal Parser that can interpret a string command
. The command
consists of an alphabet of "G"
, "()"
and/or "(al)"
in some order. The Goal Parser will interpret "G"
as the string "G"
, "()"
as the string "o"
, and "(al)"
as the string "al"
. The interpreted strings are then concatenated in the original order.
Given the string command
, return the Goal Parser's interpretation of command
.
For example:
command = "G()(al)"
, the output should be "Goal"
.command = "G()()()()(al)"
, the output should be "Gooooal"
.command = "(al)G(al)()()G"
, the output should be "alGalooG"
.Describe a function to implement the Goal Parser. What is the time and space complexity of your solution? Consider edge cases and potential optimizations.
A straightforward approach is to iterate through the input string command
and use conditional statements to check for the patterns "G", "()", and "(al)". We can build the result string by concatenating the corresponding interpretations "G", "o", and "al", respectively.
def interpret_naive(command: str) -> str:
result = ""
i = 0
while i < len(command):
if command[i] == 'G':
result += 'G'
i += 1
elif command[i:i+2] == '()':
result += 'o'
i += 2
else:
result += 'al'
i += 4
return result
The time complexity is O(n), where n is the length of the command
string, as we iterate through the string once.
The space complexity is O(n) in the worst case, as the result
string can grow up to the size of the input if the input consists only of "G" characters.
A more concise and efficient approach involves using the replace()
method to directly replace the patterns in the input string with their corresponding interpretations.
def interpret_optimal(command: str) -> str:
command = command.replace("()", "o")
command = command.replace("(al)", "al")
return command
The time complexity is O(n), where n is the length of the command
string. Although replace
might seem like O(n*m), where m is the length of the string being replaced, in this case, it simplifies to O(n) because we do not have overlapping patterns that we are trying to replace.
The space complexity is O(n) in the worst case due to the creation of new strings during the replacement operations. However, some implementations might perform the replacement in-place, leading to O(1) space complexity.
command
is an empty string, the function should return an empty string.