You are given an integer array nums
and a positive integer k
. The value of a sequence seq
of size 2 * x
is defined as: (seq[0] OR seq[1] OR ... OR seq[x - 1]) XOR (seq[x] OR seq[x + 1] OR ... OR seq[2 * x - 1])
. Return the maximum value of any subsequence of nums
having size 2 * k
.
For example:
nums = [2,6,7], k = 1
. The subsequence [2, 7]
has the maximum value of 2 XOR 7 = 5
.nums = [4,2,5,6,7], k = 2
. The subsequence [4, 5, 6, 7]
has the maximum value of (4 OR 5) XOR (6 OR 7) = 1 XOR 7 = 6
. Note that you can select any subsequence, the elements do not have to be contiguous.What is the most efficient algorithm to solve this problem? What are the time and space complexities? Discuss edge cases and how they are handled in your solution.
When you get asked this question in a real-life environment, it will often be ambiguous (especially at FAANG). Make sure to ask these questions in that case:
The brute force strategy for finding the maximum sequence value considers every possible sub-sequence within the given sequence. It calculates the sequence value for each and every sub-sequence. Finally, it compares all these values and returns the highest one found.
Here's how the algorithm would work step-by-step:
def find_maximum_sequence_value_brute_force(sequence):
maximum_sequence_value = float('-inf')
# Iterate through all possible starting positions
for start_index in range(len(sequence)):
# Iterate through all possible ending positions for each start position
for end_index in range(start_index, len(sequence)):
current_sub_sequence = sequence[start_index:end_index + 1]
current_sequence_value = calculate_sequence_value(current_sub_sequence)
# Store the max sequence value found
if current_sequence_value > maximum_sequence_value:
maximum_sequence_value = current_sequence_value
return maximum_sequence_value
def calculate_sequence_value(sub_sequence):
if not sub_sequence:
return 0
sequence_value = 0
for number in sub_sequence:
sequence_value += number
return sequence_value
The key is to avoid checking every single possible combination of numbers. Instead, focus on making choices that incrementally build the best possible result by comparing two options at each step and keeping track of what maximizes our value so far.
Here's how the algorithm would work step-by-step:
def find_maximum_sequence_value(numbers):
maximum_sequence_value = 0
current_sequence_value = 0
for number in numbers:
# Decide whether to extend the current sequence or start a new one
if current_sequence_value + number > number:
current_sequence_value += number
# Starting new sequence from current number if its greater
else:
current_sequence_value = number
# Keep track of the highest sequence value found so far
if current_sequence_value > maximum_sequence_value:
maximum_sequence_value = current_sequence_value
return maximum_sequence_value
Case | How to Handle |
---|---|
Null or empty input array | Return 0 (or throw an exception, depending on requirements) since no sequence can be formed. |
Array with one element | Return that element itself since it's the only possible sequence of length 1. |
Array with all elements equal to zero | Handle zeros appropriately; if the algorithm multiplies, make sure it doesn't cause unexpected zeros; consider zero as a valid element. |
Array with all negative numbers | The algorithm should correctly handle negative numbers and find the maximum sequence even within negative numbers. |
Large input array causing potential memory or time issues | Optimize the algorithm for time complexity and consider using data structures that minimize memory usage (e.g., in-place operations if possible). |
Integer overflow during calculations of sequence value | Use appropriate data types (e.g., long) or modulo operations to prevent integer overflow. |
Array containing extremely large or extremely small numbers | Ensure that calculations involving these numbers do not lead to overflow or underflow, potentially using larger data types or scaling techniques. |
Array with many duplicate elements that form a significant part of a possible sequence | Ensure algorithm is robust and counts each unique element only once in valid sequence or applies a count appropriately. |