Given an integer array nums
of unique elements, can you implement an algorithm to return all possible subsets (the power set)?
The solution set must not contain duplicate subsets. You can return the solution in any order.
Example 1:
Input: nums = [1,2,3]
Output: [[],[1],[2],[1,2],[3],[1,3],[2,3],[1,2,3]]
Example 2:
Input: nums = [0]
Output: [[],[0]]
Constraints:
1 <= nums.length <= 10
-10 <= nums[i] <= 10
nums
are unique.Could you provide both a naive and an optimal solution, along with their time and space complexity analysis? Also, consider edge cases such as an empty input array or an array with a single element.
When you get asked this question in a real-life environment, it will often be ambiguous (especially at FAANG). Make sure to ask these questions in that case:
The brute force method for finding all subsets means we're going to explore absolutely every possibility. We consider each item and decide whether to include it or not, building every combination imaginable. This guarantees we don't miss any subset.
Here's how the algorithm would work step-by-step:
def find_all_subsets(original_set):
list_of_all_subsets = [[]]
for current_element in original_set:
# Create a new list to hold the new subsets.
new_subsets = []
for existing_subset in list_of_all_subsets:
# Create a new subset by adding the current element to the existing subset.
new_subset = existing_subset + [current_element]
# Add the new subset to the list of new subsets.
new_subsets.append(new_subset)
# Add all the new subsets to the list of all subsets.
# This is needed to account for all possible combinations.
list_of_all_subsets.extend(new_subsets)
# Return the final list of all subsets
return list_of_all_subsets
The idea is to systematically build all possible groups, one element at a time. For each number, we decide whether to include it in our existing groups or not, effectively doubling the number of groups we have at each step. This allows us to generate all subsets in a structured manner.
Here's how the algorithm would work step-by-step:
def get_all_subsets(input_set):
all_subsets = [[]]
for number in input_set:
# Iterate through existing subsets to extend them.
new_subsets = []
for existing_subset in all_subsets:
# Create a new subset by adding the current number.
new_subset = existing_subset + [number]
new_subsets.append(new_subset)
# Add all the new subsets created in the inner loop.
all_subsets.extend(new_subsets)
return all_subsets
Case | How to Handle |
---|---|
Null or empty input array | Return a list containing only an empty set. |
Input array with a single element | Return a list containing the empty set and the set with that single element. |
Large input array (e.g., nums.length > 20) | Consider the exponential time complexity (O(2^n)) and potential for performance issues, and use bit manipulation for efficiency. |
Input array contains negative numbers | The algorithm should handle negative numbers without any issues as it operates on the presence/absence of elements, not their values. |
Input array contains zero | Zero should be treated like any other unique integer in the array, and the algorithm should correctly generate subsets including and excluding zero. |
Maximum-sized integers in the input array (Integer.MAX_VALUE) | Integer overflow is not relevant for subset generation since we're not performing arithmetic operations on the values themselves; the algorithm focuses on element inclusion. |
Duplicate numbers in the input array (violates problem statement) | Since the problem statement specifies unique integers, if duplicates are present, preprocessing might be needed to remove duplicates, or the algorithm needs to be adjusted to prevent duplicate subsets (e.g., by sorting the input and skipping duplicate elements during recursion). |
Extreme boundary values (Integer.MIN_VALUE, Integer.MAX_VALUE) | Ensure these boundary values are handled without causing issues during any internal calculations, comparisons, or data structure operations; the subset generation itself shouldn't be affected. |