Write an API that generates fancy sequences using the append, addAll, and multAll operations.
Implement the Fancy class:
Fancy() Initializes the object with an empty sequence.void append(val) Appends an integer val to the end of the sequence.void addAll(inc) Increments all existing values in the sequence by an integer inc.void multAll(m) Multiplies all existing values in the sequence by an integer m.int getIndex(idx) Gets the current value at index idx (0-indexed) of the sequence modulo 109 + 7. If the index is greater or equal than the length of the sequence, return -1.Example 1:
Input ["Fancy", "append", "addAll", "append", "multAll", "getIndex", "addAll", "append", "multAll", "getIndex", "getIndex", "getIndex"] [[], [2], [3], [7], [2], [0], [3], [10], [2], [0], [1], [2]] Output [null, null, null, null, null, 10, null, null, null, 26, 34, 20] Explanation Fancy fancy = new Fancy(); fancy.append(2); // fancy sequence: [2] fancy.addAll(3); // fancy sequence: [2+3] -> [5] fancy.append(7); // fancy sequence: [5, 7] fancy.multAll(2); // fancy sequence: [5*2, 7*2] -> [10, 14] fancy.getIndex(0); // return 10 fancy.addAll(3); // fancy sequence: [10+3, 14+3] -> [13, 17] fancy.append(10); // fancy sequence: [13, 17, 10] fancy.multAll(2); // fancy sequence: [13*2, 17*2, 10*2] -> [26, 34, 20] fancy.getIndex(0); // return 26 fancy.getIndex(1); // return 34 fancy.getIndex(2); // return 20
Constraints:
1 <= val, inc, m <= 1000 <= idx <= 105105 calls total will be made to append, addAll, multAll, and getIndex.When you get asked this question in a real-life environment, it will often be ambiguous (especially at FAANG). Make sure to ask these questions in that case:
The brute force strategy for the fancy sequence is to perform each operation one at a time directly as requested. This means applying the add, multiply, or get operation without trying to be clever or optimize anything. It's like following the instructions exactly as they are written, no shortcuts.
Here's how the algorithm would work step-by-step:
class FancySequence:
def __init__(self):
self.sequence = []
self.add_operations = []
self.multiply_operations = []
def append(self, value):
self.sequence.append(value)
def addAll(self, increment):
self.add_operations.append(increment)
def multAll(self, multiplier):
self.multiply_operations.append(multiplier)
def getIndex(self, index_to_get):
if index_to_get >= len(self.sequence):
return -1
value_at_index = self.sequence[index_to_get]
# Need to apply all operations in order
for multiplier in self.multiply_operations:
value_at_index = (value_at_index * multiplier) % 1000000007
# Need to apply all operations in order
for increment in self.add_operations:
value_at_index = (value_at_index + increment) % 1000000007
return value_at_indexThe problem asks us to efficiently perform a sequence of operations (addition, multiplication, and setting values) on a list of numbers. The key is to avoid actually updating all the numbers every time an operation is performed. Instead, we track how the operations transform the numbers indirectly using multiplicative and additive changes.
Here's how the algorithm would work step-by-step:
class FancySequence:
def __init__(self):
self.sequence = []
self.multiplicativeFactor = 1
self.additiveFactor = 0
self.modulo = 10**9 + 7
def append(self, value):
# Adjust the value to 'undo' previous operations.
adjustedValue = (value - self.additiveFactor) * self.self_inverse(self.multiplicativeFactor, self.modulo) % self.modulo
self.sequence.append(adjustedValue)
def addAll(self, increment):
# Update additive factor.
self.additiveFactor = (self.additiveFactor + increment) % self.modulo
def multAll(self, multiplier):
# Update both factors when multiplying.
self.multiplicativeFactor = (self.multiplicativeFactor * multiplier) % self.modulo
self.additiveFactor = (self.additiveFactor * multiplier) % self.modulo
def getIndex(self, indexToGet):
if indexToGet >= len(self.sequence):
return -1
# Apply cumulative operations to get final value.
rawValue = self.sequence[indexToGet]
return (rawValue * self.multiplicativeFactor + self.additiveFactor) % self.modulo
def self_inverse(self, number, modulo):
# Calculates modular inverse using Fermat's Little Theorem.
return pow(number, modulo - 2, modulo)| Case | How to Handle |
|---|---|
| Initializing with a zero-length sequence. | Handle the empty sequence by initializing the sequence with an empty list and setting the multiplier and adder to default values (e.g., 1 and 0). |
| Adding a very large number of elements to the sequence, exceeding memory limits. | Consider using a modular arithmetic approach and pre-allocate memory if the sequence size is known in advance or implement a dynamic resizing strategy with checks to prevent memory overflow. |
| Multiplying by zero. | Reset the multiplier to 1 to avoid making all subsequent elements zero. |
| Adding an extremely large or small number, leading to integer overflow/underflow in getIndex. | Use modular arithmetic with a large prime number during calculations in `add` and `getIndex` operations to avoid exceeding the maximum integer value. |
| Repeatedly multiplying without adding, leading to extremely large multiplier value. | Apply modular arithmetic on the multiplier itself to prevent overflow. |
| Calling getIndex with an index that is too small before any operations have been performed. | Return 0 if the index is out of the current bounds of the sequence, consistent with initializing the sequence with zeros. |
| Alternating add and multiply operations causing significant precision loss in the multiplier or adder (if using floats). | Stick to integer arithmetic and modular operations if floating-point precision is a concern for a specific application. |
| Modular inverse does not exist during division operation when reversing the operations for getIndex because the multiplier is not coprime to mod. | Implement a mechanism to detect when the modular inverse does not exist and signal an error or fallback to a slower, but more robust calculation. |