Given an array of integers citations where citations[i] is the number of citations a researcher received for their ith paper, return the researcher's h-index.
According to the definition of h-index on Wikipedia: The h-index is defined as the maximum value of h such that the given researcher has published at least h papers that have each been cited at least h times.
Example 1:
Input: citations = [3,0,6,1,5] Output: 3 Explanation: [3,0,6,1,5] means the researcher has 5 papers in total and each of them had received 3, 0, 6, 1, 5 citations respectively. Since the researcher has 3 papers with at least 3 citations each and the remaining two with no more than 3 citations each, their h-index is 3.
Example 2:
Input: citations = [1,3,1] Output: 1
Constraints:
n == citations.length1 <= n <= 50000 <= citations[i] <= 1000When you get asked this question in a real-life environment, it will often be ambiguous (especially at FAANG). Make sure to ask these questions in that case:
To find the h-index, we're going to try every possible value for the h-index. For each potential h-index, we'll check if the list of publications meets the required criteria to actually have that h-index.
Here's how the algorithm would work step-by-step:
def h_index_brute_force(citations):
# Iterate through possible h-index values
for possible_h_index in range(len(citations) + 1):
# Count publications with at least possible_h_index citations
publications_with_enough_citations = 0
for citation_count in citations:
if citation_count >= possible_h_index:
publications_with_enough_citations += 1
# If we don't have enough publications for this h-index, return the previous one
if publications_with_enough_citations < possible_h_index:
# Previous h-index is the result
return possible_h_index - 1
# If the loop completes, the h-index is the number of publications
return len(citations)The H-Index represents the highest number 'h' such that the researcher has 'h' papers that have each been cited at least 'h' times. The most efficient approach leverages sorting to quickly identify this 'h' without exhaustively checking every possibility. By sorting, we can efficiently determine the H-Index by working our way down the sorted list of citations.
Here's how the algorithm would work step-by-step:
def calculate_h_index(citation_counts):
citation_counts.sort(reverse=True)
h_index = 0
for index, citation_count in enumerate(citation_counts):
# The index is incremented by 1 to represent position.
position = index + 1
# Check if the citation count meets the h-index criterion.
if citation_count >= position:
h_index = position
else:
# Once the condition is no longer met, the h-index is found.
break
return h_index| Case | How to Handle |
|---|---|
| Empty or null input array | Return 0 immediately as no publications exist. |
| Array with a single element where the citation is 0 | Return 0 because the single publication has insufficient citations. |
| Array with a single element where the citation is a large positive integer | Return 1 as the researcher has 1 paper with at least 1 citation. |
| Array with all citations equal to zero | Return 0 as no paper has any citations, making the h-index 0. |
| Array with all citations greater than or equal to the number of papers | Return the length of the array, as all papers have citations at least equal to the number of papers. |
| Array with citations in descending order (e.g., [5, 4, 3, 2, 1]) | The h-index will be determined by the index where citations[i] < i + 1. |
| Array with citations in ascending order (e.g., [0, 1, 2, 3, 4]) | The h-index should be calculated based on the number of citations greater than or equal to that number. |
| Large input array with very large citation values that might cause integer overflow during counting sort. | Cap the count array size by the number of citations or use a different sorting algorithm like comparison sort for efficiency. |