You are given a string num representing a large integer. An integer is good if it meets the following conditions:
num with length 3.Return the maximum good integer as a string or an empty string "" if no such integer exists.
Note:
num or a good integer.Example 1:
Input: num = "6777133339" Output: "777" Explanation: There are two distinct good integers: "777" and "333". "777" is the largest, so we return "777".
Example 2:
Input: num = "2300019" Output: "000" Explanation: "000" is the only good integer.
Example 3:
Input: num = "42352338" Output: "" Explanation: No substring of length 3 consists of only one unique digit. Therefore, there are no good integers.
Constraints:
3 <= num.length <= 1000num only consists of digits.When you get asked this question in a real-life environment, it will often be ambiguous (especially at FAANG). Make sure to ask these questions in that case:
The brute force method in this case means checking every possible group of three digits next to each other in the string. We look at each such group and see if all three digits are the same, and keep track of the largest such group we find.
Here's how the algorithm would work step-by-step:
def find_largest_3_same_digit_number(number_string):
largest_3_same_digits = ""
for index in range(len(number_string) - 2):
# Check every possible group of three digits
group_of_three = number_string[index:index + 3]
#If the characters in the substring are all equal
if group_of_three[0] == group_of_three[1] == group_of_three[2]:
#Convert the current substring and the largest one seen so far to integers and perform a comparison
if largest_3_same_digits == "" or int(group_of_three) > int(largest_3_same_digits):
largest_3_same_digits = group_of_three
return largest_3_same_digitsThe best way to find the largest same-digit number is to check each possible three-digit sequence in the input string and keep track of the largest one seen so far. We can efficiently update the largest same-digit number by directly comparing the numerical values of the digits we find.
Here's how the algorithm would work step-by-step:
def largest_3_same_digit_number(number):
largest_number = ""
for i in range(len(number) - 2):
# Extract a sequence of 3 digits.
three_digit_sequence = number[i:i+3]
# Check if all 3 digits are the same
if three_digit_sequence[0] == three_digit_sequence[1] == three_digit_sequence[2]:
# Update largest number if needed. Converting to int for comparison.
if largest_number == "" or int(three_digit_sequence[0]) > int(largest_number[0]):
largest_number = three_digit_sequence
return largest_number| Case | How to Handle |
|---|---|
| Empty string input | Return an empty string immediately as there are no digits to form a 3-same-digit number. |
| String length less than 3 | Return an empty string since a 3-same-digit number cannot be formed. |
| String contains non-digit characters | The solution should only process digit characters and ignore any non-digit characters encountered. |
| String contains no 3-same-digit numbers | Return an empty string to indicate that no such number was found. |
| Multiple 3-same-digit numbers exist; find the largest | The solution should iterate through all possible 3-same-digit numbers and return the largest one encountered. |
| String contains only one type of digit, repeated fewer than 3 times | Return an empty string as the condition for 3 same digits is not met. |
| String begins with leading zeros | Handle leading zeros correctly, e.g., '000123' should potentially return '000' if it's the largest. |
| Very long input string | The solution should iterate efficiently through the string to avoid time complexity issues. |