You are given a 0-indexed integer array nums. You can rearrange the elements of nums to any order (including the given order).
Let prefix be the array containing the prefix sums of nums after rearranging it. In other words, prefix[i] is the sum of the elements from 0 to i in nums after rearranging it. The score of nums is the number of positive integers in the array prefix.
Return the maximum score you can achieve.
Example 1:
Input: nums = [2,-1,0,1,-3,3,-3] Output: 6 Explanation: We can rearrange the array into nums = [2,3,1,-1,-3,0,-3]. prefix = [2,5,6,5,2,2,-1], so the score is 6. It can be shown that 6 is the maximum score we can obtain.
Example 2:
Input: nums = [-2,-3,0] Output: 0 Explanation: Any rearrangement of the array will result in a score of 0.
Constraints:
1 <= nums.length <= 105-106 <= nums[i] <= 106When you get asked this question in a real-life environment, it will often be ambiguous (especially at FAANG). Make sure to ask these questions in that case:
The brute force approach tackles this problem by trying absolutely every single possible arrangement of the numbers. For each arrangement, we calculate a 'score' to see how good it is, and at the end, we pick the arrangement with the best score. It's like trying every combination lock setting until you find the right one.
Here's how the algorithm would work step-by-step:
def rearrange_array_brute_force(numbers):
best_score = float('-inf')
best_arrangement = []
def calculate_prefix_score(arrangement):
current_score = 0
prefix_sum = 0
for number in arrangement:
prefix_sum += number
if prefix_sum > 0:
current_score += 1
return current_score
def generate_permutations(index, current_arrangement):
nonlocal best_score
nonlocal best_arrangement
if index == len(numbers):
# We have a complete arrangement; calculate score and update if necessary
current_score = calculate_prefix_score(current_arrangement)
if current_score > best_score:
best_score = current_score
best_arrangement = current_arrangement[:]
return
for i in range(index + 1):
# Try inserting the current number at every possible position
new_arrangement = current_arrangement[:i] + [numbers[index]] + current_arrangement[i:]
# Recursively generate permutations with the new arrangement
generate_permutations(index + 1, new_arrangement)
# Start generating permutations from the beginning
generate_permutations(0, [])
return best_arrangementTo maximize the prefix score, we need to arrange the input numbers in a special order. The key idea is to prioritize putting larger numbers earlier in the sequence, because they contribute more to the sums that make up the score.
Here's how the algorithm would work step-by-step:
def rearrange_array_to_maximize_prefix_score(numbers):
# Sort the numbers in descending order
numbers.sort(reverse=True)
prefix_sums = []
current_prefix_sum = 0
for number in numbers:
current_prefix_sum += number
prefix_sums.append(current_prefix_sum)
# Calculate the score by summing up all prefix sums
total_score = sum(prefix_sums)
return total_score| Case | How to Handle |
|---|---|
| Null or empty input array | Return an empty array or throw an IllegalArgumentException, depending on the specified behavior. |
| Array with one element | Return the array as is, as no rearrangement is possible. |
| Array with all identical values | Sorting the array will not change its order, but it should still produce a valid, although not necessarily 'optimized', score; the solution should execute without errors. |
| Array with extremely large numbers that could lead to integer overflow when summing the prefix | Use a data type with a larger range, like long, to store the prefix sums and handle potential overflows. |
| Array with very large input size (e.g., 10^5 or more elements) | Ensure that the sorting algorithm used is efficient (e.g., O(n log n)) to avoid exceeding time limits. |
| Array with negative numbers, potentially causing negative prefix scores. | The algorithm should correctly handle negative prefix scores without errors and optimize to maximize the sum even with negative values. |
| Array contains a mix of large positive and large negative numbers that could result in an intermediate overflow, even with long. | Consider using a datatype that can handle larger ranges than long or using an alternative algorithm that avoids intermediate sums, if feasible. |
| Array with input values equal to max or min integer values | Check for integer overflow/underflow issues and handle them by casting to long before operations and casting back, handling overflow by using max or min long values |