You are given a string s and an integer t, representing the number of transformations to perform. In one transformation, every character in s is replaced according to the following rules:
'z', replace it with the string "ab".'a' is replaced with 'b', 'b' is replaced with 'c', and so on.Return the length of the resulting string after exactly t transformations.
Since the answer may be very large, return it modulo 109 + 7.
Example 1:
Input: s = "abcyy", t = 2
Output: 7
Explanation:
'a' becomes 'b''b' becomes 'c''c' becomes 'd''y' becomes 'z''y' becomes 'z'"bcdzz"'b' becomes 'c''c' becomes 'd''d' becomes 'e''z' becomes "ab"'z' becomes "ab""cdeabab""cdeabab", which has 7 characters.Example 2:
Input: s = "azbk", t = 1
Output: 5
Explanation:
'a' becomes 'b''z' becomes "ab"'b' becomes 'c''k' becomes 'l'"babcl""babcl", which has 5 characters.Constraints:
1 <= s.length <= 105s consists only of lowercase English letters.1 <= t <= 105When you get asked this question in a real-life environment, it will often be ambiguous (especially at FAANG). Make sure to ask these questions in that case:
The brute force way to solve this is to try every single possible transformation of the string. This means going through each character in the string and deciding whether or not to perform the transformation on it. Then, for each potential transformation, we measure the length of the string and see if it is the shortest we've encountered.
Here's how the algorithm would work step-by-step:
def total_characters_in_string_after_transformations_i_brute_force(input_string):
number_of_characters = len(input_string)
minimum_length = number_of_characters
# Iterate through all possible combinations of transformations
for i in range(2 ** number_of_characters):
transformed_string = ""
# Build the transformed string based on the current combination
for character_index in range(number_of_characters):
# Check if the character should be transformed
if (i >> character_index) & 1:
# Applying transformation as described in problem
transformed_string += ""
else:
transformed_string += input_string[character_index]
# Update minimum length if necessary
current_length = len(transformed_string)
# Keep track of shortest string length that we've encountered
if current_length < minimum_length:
minimum_length = current_length
return minimum_lengthThe most efficient strategy involves recognizing that identical characters next to each other can be simplified. We can significantly reduce the string length by only keeping one instance of a repeated character.
Here's how the algorithm would work step-by-step:
def total_characters_after_transformations(input_string):
transformed_string = ""
if not input_string:
return 0
transformed_string += input_string[0]
# Iterate through the input string starting from the second character.
for index in range(1, len(input_string)):
# Only append the character if it's different from the last one.
if input_string[index] != transformed_string[-1]:
transformed_string += input_string[index]
return len(transformed_string)| Case | How to Handle |
|---|---|
| Null input string | Return 0 or throw an IllegalArgumentException, based on requirements/convention. |
| Empty input string | Return 0 as there are no characters to transform. |
| String with only one unique character | Handle based on the transformation rules; may result in the same total characters or a reduced number. |
| String with no transformations possible based on given rules | Return the original string length as no characters are removed or added. |
| Maximum-length string (considering memory constraints) | Ensure algorithm has acceptable time and space complexity, potentially using StringBuilder efficiently. |
| String with unicode characters | Ensure character comparisons and manipulations handle unicode characters correctly (e.g., using code points). |
| String with special characters or whitespace | Handle whitespace and special characters based on transformation rules; they might be skipped or treated as normal chars. |
| Very long string where intermediate calculations might cause overflow | Use appropriate data types (e.g., long) to prevent integer overflow during calculations of lengths or counts. |