There is a website where users can perform purchase transactions. Each transaction consists of the ID of the user, the timestamp of the transaction, and the amount of the transaction.
Implement the UserPurchasePlatform class:
UserPurchasePlatform() Initializes the object.void addTransaction(int userId, int timestamp, int amount) Adds the transaction with userId, timestamp and amount to the platform.int calculateSpending(int userId, int startTime, int endTime) Returns the total amount spent by user with ID userId in the inclusive time range [startTime, endTime].Example:
Input
["UserPurchasePlatform", "addTransaction", "calculateSpending", "addTransaction", "calculateSpending", "addTransaction", "calculateSpending"]
[[], [1, 1, 10], [1, 0, 10], [2, 2, 20], [2, 0, 20], [1, 3, 30], [1, 0, 30]]
Output
[null, null, 10, null, 20, null, 40]
Explanation
UserPurchasePlatform userPurchasePlatform = new UserPurchasePlatform();
userPurchasePlatform.addTransaction(1, 1, 10); // add a transaction for user 1 at time 1 with amount 10
userPurchasePlatform.calculateSpending(1, 0, 10); // return the total amount spent by user 1 in the time range [0, 10]. Answer: 10
userPurchasePlatform.addTransaction(2, 2, 20); // add a transaction for user 2 at time 2 with amount 20
userPurchasePlatform.calculateSpending(2, 0, 20); // return the total amount spent by user 2 in the time range [0, 20]. Answer: 20
userPurchasePlatform.addTransaction(1, 3, 30); // add a transaction for user 1 at time 3 with amount 30
userPurchasePlatform.calculateSpending(1, 0, 30); // return the total amount spent by user 1 in the time range [0, 30]. Answer: 10 + 30 = 40
Constraints:
1 <= userId, timestamp, amount <= 10001000 calls will be made to addTransaction and calculateSpending.When you get asked this question in a real-life environment, it will often be ambiguous (especially at FAANG). Make sure to ask these questions in that case:
The brute force approach to this problem means we're going to try every single possible combination of purchases to see which one is the best. We will methodically check each possible purchase and see if it satisfies some pre-defined conditions. We continue this process until we find the best option, no matter how long it takes.
Here's how the algorithm would work step-by-step:
def find_eligible_purchases_brute_force(users, items):
eligible_purchases = []
for user in users:
for item in items:
# Check eligibility for each user-item pair
if is_eligible_to_purchase(user, item):
# Only add if user is eligible.
eligible_purchases.append((user, item))
return eligible_purchases
def is_eligible_to_purchase(user, item):
# Dummy logic - replace with actual rules
# This is where the eligibility logic goes
user_location = user.get('location')
item_location = item.get('available_location')
if item_location == "global" or user_location == item_location:
user_age = user.get('age')
# Adding age check
if user_age is not None and user_age >= item.get('min_age', 0):
return True
return False
# Example usage (for demonstration purposes)
if __name__ == '__main__':
users = [
{'user_id': 1, 'location': 'USA', 'age': 25},
{'user_id': 2, 'location': 'Canada', 'age': 17},
{'user_id': 3, 'location': 'USA', 'age': 30}
]
items = [
{'item_id': 101, 'available_location': 'USA', 'min_age': 18},
{'item_id': 102, 'available_location': 'Canada', 'min_age': 21},
{'item_id': 103, 'available_location': 'global', 'min_age': 0}
]
eligible = find_eligible_purchases_brute_force(users, items)
for user, item in eligible:
print(f"User {user['user_id']} is eligible to purchase item {item['item_id']}")The challenge involves processing user purchase data to efficiently determine which products were bought together most frequently. The optimal strategy involves counting these co-occurrences and then identifying the top ones. This avoids repeatedly searching through the entire dataset for each possible pair.
Here's how the algorithm would work step-by-step:
def find_frequent_purchase_patterns(purchase_records):
user_purchase_sequences = {}
for user, time, platform in purchase_records:
if user not in user_purchase_sequences:
user_purchase_sequences[user] = []
user_purchase_sequences[user].append((time, platform))
platform_sequences = []
for user, purchases in user_purchase_sequences.items():
# Sort purchases by time.
purchases.sort()
platforms = [platform for _, platform in purchases]
# Create sequences of platforms for each user.
for i in range(len(platforms) - 1):
sequence = tuple(platforms[i:i+2])
platform_sequences.append(sequence)
sequence_counts = {}
# Count the frequency of each platform sequence.
for sequence in platform_sequences:
if sequence not in sequence_counts:
sequence_counts[sequence] = 0
sequence_counts[sequence] += 1
# Find the most frequent platform sequences.
sorted_sequences = sorted(sequence_counts.items(), key=lambda item: item[1], reverse=True)
most_frequent_sequences = []
if sorted_sequences:
max_frequency = sorted_sequences[0][1]
for sequence, frequency in sorted_sequences:
if frequency == max_frequency:
most_frequent_sequences.append((sequence, frequency))
else:
break
return most_frequent_sequences| Case | How to Handle |
|---|---|
| Empty purchases list | Return an empty commission dictionary as there are no purchases to calculate commissions from. |
| Empty commissions list | Return an empty commission dictionary as there are no platforms to attribute commissions to. |
| Null purchases or commissions lists | Throw an IllegalArgumentException or return an error code to indicate invalid input. |
| Purchase with zero or negative amount | Either ignore these purchases or throw an exception depending on requirements; negative amounts likely indicate errors. |
| Commission rate is zero | The platform will earn zero commission for purchases assigned to it, which is a valid (though possibly unexpected) outcome. |
| Commission rate is negative | Throw an exception or treat as zero, as negative commissions are not logical. |
| User ID or Item ID is null or empty string | Handle the invalid User ID/Item ID by ignoring it, logging the error, or throwing an exception based on the requirements. |
| Very large number of purchases causing integer overflow when calculating total commissions | Use long or BigInteger to prevent integer overflow when summing the commissions. |